9:35 Exam II Key; SPRING 2020 Dr. Williamson
| Pink, | Blue, | QUESTION | Yellow, Exam II, v3 |
| 5.5 | 5.5 | 5.5 pts each unless noted | |
| A | A | 1 | D |
| D | A | 2 | E |
| A | E (D= 3PTS) | 3 | C |
| B | C | 4 | A |
| B | B | 5 | B |
| B | A | 6 | E |
| D | D | 7 | D |
| B (E= 3PTS) | B | 8 | E |
| D | B | 9 | E (B= 3PTS) |
| A | B (A= 4 PTS) | 10 | D |
| B | D | 11 | E (A= 3PTS) |
| E (C= 4 PTS) | C (A= 3PTS) | 12 | C |
| B | C | 13 | B (A= 4 PTS) |
| D (B= 3PTS) | B | 14 | A |
(14 MC x 5.5 pts each) = 77 pts + short answer 23 pts = 100 pts on the total exam
To find your grade: (the number of MC questions you got totally correct x 5.5) + any partial points = the total multiple choice out of 77. Later you will add to this your short answer grade (deducting 2 pts if you did NOT bubble your name and UIN correctly)
For short answer, if you gave both the electronic and molecular geometry, BUT did not indicate which was the shape, then 1 pt for shape. The shape, hybridization, and polarity must match your drawing for credit on those. Answers are in the glass case in the hallway near 123 HELD.
| Species | val. e- 1pt |
drawing 3pt |
brackets & ion charge 1pt |
shape of molecule |
hybrid. 2pt |
Polar or nonpolar 2pt |
Dissolve H2O or CCl4 |
|
|---|---|---|---|---|---|---|---|---|
| Pink | IBr5 | 42 | 5 single bonds and 1 lone e- pair on central atom | --- | Square Pyramidial | sp3d2 | polar | water |
| Pink | NO2- | 18 | 1 single bond, 1 double bond and 1 lone pair on central atom | yes | bent | sp2 | polar | -- |
| Blue | IF3 | 28 | 3 single bond and 2 lone e- pair on central atom | --- | T-shaped | sp3d | polar | water |
| Blue | CO2-2 | 18 | 1 single b, 1 double b. and 1 lone e- pair on central atom with a neg. charge | yes | bent | sp2 | polar | -- |
| Yellow | OBr2 | 20 | 2 single bonds and 2 lone electron pair on central atom | --- | bent | sp3 | polar | water |
| Yellow | ICl4- | 36 | 4 single b. and 2 lone e- pair on central atom with a neg. charge | yes | square planar | sp3d2 | nonpolar | -- |